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3) Moment of inertia for cylinder (part 2)
The equation for the moment of inertia for a cylinder that has a rotation center
such as shown in Fig. 3-16 is given below.
ρπ D h
2
2
D
I=
(
16
4
ρπ D h
2
2
D
(
J=
16g
4
ρ : Density (kg/m
g : Gravitational acceleration (cm/sec
m : Mass of cylinder (kg)
W : Weight of cylinder (kgf)
4) Moment of inertia for prism
The equation for the moment of inertia for a prism that has a rotation center
as shown in Fig. 3-17 is given as follows.
ρ abc(a +b )
2
2
m(a +b )
I=
=
12
ρ abc(a +b )
2
2
W(a +b )
J=
=
12g
ρ : Density (kg/m
g : Gravitational acceleration (cm/sec
m : Mass of prism (kg)
W : Weight of prism (kgf)
2
2
h
D
m
+
)
=
(
3
4
4
2
2
h
D
W
)
(
+
=
3
4
4g
3
3
, kg/cm
)
2
)
2
2
2
(kgm
)
12
2
2
2
(kgfcmsec
12g
... (Eq. 3.4)
c
b
3
3
, kg/cm
)
2
)
3-21
CHAPTER 3 Installation
2
h
2
+
)
(kgm
)
3
2
h
2
)
(kgfcmsec
)
+
3
D
Fig. 3-16
)
Fig. 3-17
... (Eq. 3.3)
h
2
h
1/2a
a
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