Huawei NetCol5000-A050 Quick Manual page 24

11.3
Precharging Refrigerant
If the R410A refrigerant is provided by Huawei, put the refrigerant steel vessel upside down
when charging in the refrigerant. If the refrigerant is not provided by Huawei, check with the
refrigerant provider whether the steel vessel has a siphon. If the vessel has a siphon, put it
upside up when charging in refrigerant. If the vessel has no siphon, put it upside down when
charging in refrigerant. These measures ensure that the refrigerant is charged in the liquid
form.
1. Remove the vacuum pump from the vacuuming equipment, and replace the vacuum
pump with a refrigerant steel vessel.
2. Partially open the refrigerant steel vessel valve and rubber tube nut. Tighten the nut
when you feel cold air coming out from the nut.
3. Put the refrigerant steel vessel upside down on an electric balance. Clear the reading on
the balance.
4. Open pressure gauge valves, and the refrigerant steel vessel valve to charge refrigerant.
5. The amount of refrigerant charged must be more than half of the total charge amount
calculated and less than the total charge amount. Charge the remaining refrigerant
during power-on commissioning.
6. After refrigerant charging, close pressure gauge valves, and the refrigerant steel vessel
valve.
Amount of refrigerant to be charged for the NetCol5000-A
Refrigerant Length of the One-
Charge Amount Way Connection Pipe
Between the Indoor
and Outdoor Units (L)
Standard charge ≤ 10 m
amount (kg)
Charge amount 10 m < L ≤ 60 m
(kg) = Standard
charge amount +
Extra charge
amount
Charge amount 60 m < L ≤ 100 m
(kg) = Standard
charge amount +
Extra charge
amount
When the outdoor unit is NetCol500-A120, the outdoor unit can be separately connected to two
indoor units.
NetCol500- NetCol500-A060
A060 with a Low
(NetCol500- Temperature
A120) Component
9.2 35.8
9.2 + (L – 10) 35.8 + (L – 10) x
x 0.19 0.19
9.2 + (L – 10) 35.8 + (L – 10) x
x 0.25 0.25
24
NetCol500 NetCol500
-A080 -W055
13.2 10
13.2 + (L – 10 + (L –
10) × 0.19 10) × 0.21
13.2 + (L – 10 + (L –
10) × 0.25 10) × 0.28