Calculation example
Drive:
•
ACS800-04-0075-3
•
supply voltage U = 410 V
Transformer:
•
rated power S
•
rated voltage U
•
transformer impedance z
Supply cable:
•
length = 170 m
•
resistance/length = 0.398 ohm/km
•
reactance/length = 0.082 ohm/km.
The calculated short-circuit current 2.7 kA is higher than the minimum short-circuit current of the drive
gG fuse type OFAF00H160 (2400 A). -> The 500 V gG fuse (ABB Control OFAF00H160) can be used.
Phone: 800.894.0412 - Fax: 888.723.4773 - Web: www.clrwtr.com - Email: info@clrwtr.com
= 600 kVA
N
= 430 V
N
= 7.2%.
k
2
U
(430 V)
N
·
Z
= z
·
= 0.072
k
k
S
600 kVA
N
ohm
m · 0.398
R
= 170
c
km
ohm
m · 0.082
X
= 170
c
km
410 V
I
=
k2-ph
(67.66 mohm)
2 ·
2
= 22.19 mohm
= 67.66 mohm
= 13.94 mohm
2
+ (22.19 mohm + 13.94 mohm)
= 2.7 kA
2
Technical data
97