Test Example 2 - GE T60 Instruction Manual

Transformer protection system ur series
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8 COMMISSIONING
D/YG30° TRANSFORMER WITH PHASE A TO GROUND FAULT ON THE GROUNDED WYE.
Transformer: D/y30°, 20 MVA, 115/12.47 kv, CT1 (200:1), CT2 (1000:1)
I (f) = 0.577 pu 0°
A
A
I (f) = 0 pu
B
B
C
I (f) = 0.577 pu –180°
C
Figure 8–3: CURRENT DISTRIBUTION ON A D/YG30° TRANSFORMER WITH A LV-SIDE GROUND FAULT
TEST
PHASE
W1 CURRENT
0.29 0°
Balanced
A
Condition
B
0.29 –180°
C
0.137 0°
Minimum
A
Pickup
B
0.137 –180°
C
0.108 0°
Minimum
A
Pickup
B
0.108 –180°
C
0.4435 0°
Slope 1
A
B
0.4435 –180°
C
0.4425 0°
Slope 1
A
B
0.4425 –180°
C
1.2 0°
Intermediate
A
Slope 1 & 2
B
1.2 –180°
C
1.1 0°
Intermediate
A
Slope 1 & 2
B
1.1 –180°
C
0.4 0°
Slope 2
A
B
0.4 –180°
C
0.2 0°
Slope 2
A
B
0.2 –180°
C
GE Multilin
D/y30° Transformer
INJECTED CURRENT
W2 CURRENT
0.926 –180°
0 0°
0 0°
0 0°
0.521 –180°
0 0°
0 0°
0 0°
0.521 –180°
0 0°
0 0°
0 0°
1.6 –180°
0 0°
0 0°
0 0°
1.7 –180°
0 0°
0 0°
0 0°
5 –180°
0 0°
0 0°
0 0°
5 –180°
0 0°
0 0°
0 0°
15 –180°
0 0°
0 0°
0 0°
15 –180°
0 0°
0 0°
0 0°
T60 Transformer Protection System
8.2 DIFFERENTIAL CHARACTERISTIC TEST EXAMPLES
I (f) = 1 pu 0°
a
I (f) = 0
b
I (f) = 0
c
DISPLAYED CURRENT
DIFFERENTIAL
RESTRAINT
0 0°
0.5349 –180°
0 0°
0 0°
0 0°
0.5349 0°
0.048 0°
0.3 –180°
0 0°
0 0°
0.048 0°
0.3 0°
0.102 0°
0.3 –180°
0 0°
0 0°
0.102 0°
0.3 0°
0.110 0°
0.9026 –180°
0 0°
0 0°
0 0°
0 0°
0.165 0°
0.979 –180°
0 0°
0 0°
0.165 0°
0.979 0°
0.675 –180°
2.882 –180°
0 0°
0 0°
0.675 0°
2.882 0°
0.860 –180°
2.882 –180°
0 0°
0 0°
0.860 0°
2.882 0°
7.915 –180°
8.646 –180°
0 0°
0 0°
7.915 0°
8.646 0°
7.918 –180°
8.650 –180°
0 0°
0 0°
7.916 0°
8.650 0°

8.2.3 TEST EXAMPLE 2

A
Fault
B
C
828737A1.CDR
STATUS
Not Applicable
Block
I
= 0.048 < Min PKP
d
Operate
I
= 0.102 > Min PKP
d
Block
I
I
/
= 11.9%
d
r
Operate
I
I
/
= 16.8%
d
r
Block
I
I
/
= 23.4%
d
r
Operate
I
I
/
= 29.8%
d
r
Block
I
I
/
= 91.5%
d
r
Operate
I
I
/
= 95.7%
d
r
8
8-9

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