Single AC input
Define the average motoring line current I
=
•
I
mot,ave
Define the peak motoring line current I
=
I
•
mot,
max
The factor 1.15 covers the effects of line side power factor, current harmonic
distortion and rectifier losses.
The following conditions must be fulfilled.
<
•
I
mot
,
ave
<
I
•
mot
,max
Multiple AC input
In case two or more drive modules are connected to the AC supply, the
same conditions as above must still be fulfilled, but now for each individual
drive module (i) and its mains choke separately.
I
•
mot
,
ave
(
) i
•
I
mot
,max(
) i
where the total motoring line current is allocated to the individual drive
modules according to their power ratings:
•
I
mot
,
ave
(
) i
I
•
mot
,max(
) i
where
•
I
and I
mot,ave(i)
input,
•
P
and P
rec,ave(i)
connected to the concerned AC input,
•
P
... P
rec,ave1
drive modules connected to the AC input.
•
The factor 1.20 covers the load unbalance due to the variation of the
characteristics of the individual choke(s) and drive module(s) from
the nominal ones.
•
I
and I
mot,ave
single AC input case.
P
×
mot
,
ave
1
.
15
×
3
U
ac
P
×
1
.
15
mot
,max
×
3
U
ac
I
th
I
max
<
I
th
(
) i
<
I
max(
) i
=
×
1
.
20
+
(
P
P
rec
,
ave
1
=
×
1
.
20
+
(
P
rec
,max
1
are the AC input currents of the concerned AC
mot,max(i)
are the power ratings of the drive module
rec,max(i)
and P
rec,aven
rec,max1
are calculated from P
mot,max
mot,ave
mot,max
P
rec
,
ave
(
) i
+
+
...
P
rec
,
ave
2
rec
,
aven
P
rec
,max(
) i
+
+
P
...
P
rec
,max
2
rec
,max
... P
are the power ratings of the
rec,maxn
and P
mot,ave
19
×
I
mot
,
ave
)
×
I
mot
,max
)
n
as in the
mot,max