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Note the relatively large value for f(x). There is no value of x for which
f(x) equals 0. However, at x=2.0000,
finds two neighboring
values of x that yield opposite signs for f(x).
f(x)
o)
T 1
Bt
+
}
}
-
1
}
X
-2
4
)
+ —1
oo)
T+ —2
Dy
f(x) = IP(x) — 1.5 = 0
Example: A Pole. Find the root of the equation:
SOLVE Equation: X+ (X"2-6)-1=8
As x approaches \/6 , f(x) becomes a very large positive or negative
number:
Keys:
Display:
Description:
2.3
X
Calculates the root usin
2.7 @(SOLVE]
%X=2.4495
guesses that bracket
\/6 .
B (LAsST]
81,649,658,092.0
f(x) is relatively large.
162
B: More About Solving Equations
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