Philips PM2517E Service Manual page 77

I
I
I
I
6.3.2. Dlsplay constant 0 (Overrang€)
6.3.3. Display will nol become zero with shorcircuiled ADC input
73
N o . From
M e a s u r e m e n t
M e a s u r i n g p o i n t s
M e a s u r i n g d a t a C o r r e c t t n c o r r e c l
O v e r r a n g e ( O V R )
h E F 4 5 5 5 ( 0 7 0 2 )
H i = D 7 O 2 1 1
S h o r t c i r c u i l A D C i n p u t
L o q r c 0 ( - 8 5 V )
D e l e c l H E F 4 5 5 5
\ o 7 4 2 )
R e l e r l o B
a
O v e f f a n g e ( O V B )
oQ0059
H i = D 1 0 r / 1 9 ,
Shorrcircuit aDC in put
L o s c 0 ( - 8 5 V ) T r a c k n 1 7 0 2 ) R e f e r l o I
B
O v e r r a n q e ( O V R )
oo0059
1 D 1 0 r )
H i = D l 0 1 / 1 9 ,
S h o r t c i r c u i t A D C n p u t
L o q i c 0 ( - 8 5 V )
R e l e r r o C
c
B
D a t a s i g n a l 0 0 0 0 6 0
( a r 0 1 )
H i = 4 1 0 1 / 1 5 r
S h o n c i r c u i t A D C i n p u l
c L o c k 4 1 0 1 / 2 8 0 . . 1 2 0 k H 2
D A T A 4 1 0 1 / 1 5 T , x c l o c k
J-l_-l_-L
s y m m e l n c a l
Delect O00059
I n p u i A D C ;
H i = R 1 0 8 r i g h l
h a n d s i d e
I
N o .
F r o m V l e a s u r e m e n t l \ 4 e a s u r i n g
p o i n t s
l V e a s u r i n g d a t a Correct t n c o r r e c l
l r e t O Q 0 0 6 4
( 4 1 0 2 )
H i : 4 1 0 2 i 1 4
S h o r t c l r c u i l A D C i n p u t
R e l e r t o B
C h e c k a d l u s l m e n l s i
. R e f e r e n c e c u r r e n t
A D C ( a d J . n o . 2 )
. R a n g e 2 o l A D C
( a d t . n o . 4 )
R r 0 7
R 1 0 6
S h o r t c r r c u i t / D C I n p l ] l
R l 0 7 a d i u s l n g r e s r s l o r
9 k 5 3 . . . 1 6 k 2
P o t e n i i o m e t e r 2 k 2
R 1 0 5 = 1 0 k 2
D e l e c t O Q 0 0 6 4
c
lref 000064
(4r02)
H = A l 0 2 / 1 4 ,
W i l h o s c i l l o s c o p e
S h o r i c r c u i t A D C i n p u t
O s c a t i o n s
C h e c k c a p a c l o r
c ] 1 0
R e f e r t o D
D C l n p u t o f A D C
S w r t c h r n g P a (
o o 0 0 6 0 A ( 1 0 r )
H = A 1 0 r / 1 0
H = 4 1 0 1 / 1 2 I
^,^w.V.
>lomv
D e f e c t O 0 0 0 6 0
C h e c k : C 1 0 3 . R 1 0 4
T r a c k I n l e r r u p l r o n
l n p u t A D C i
H i = F 1 0 8
n g h l h a n d s d e
6.3.4. No adjustment ol instrument possible, stable display, input vollage supplied lo ADC
N o .
From
M e a s u r e m e n t
N 4 e a s u r i n g
p o i n t s
M e a s u r i n g d a t a
C o r r e c t
l n c o r r e c t
l r e t O Q 0 0 6 4
( A 1 0 2 )
Hi = A1A2l14
S h o r l c i r c u i l A D C i n p u l
+ lz0pA R e l e r t o C , O E , F F e i e r t o B
Check
F r 0 5 . R 1 0 6 , R r 0 7
a n d R ] 1 3
R r 0 5 . R r 0 6 , R 1 0 7 ,
R 1 1 3
R l 0 5 = 1 0 k 2
R106 = 2k2 polenirometer
R 1 0 7 = A d J u s t i n g
9 k 5 3 . r 6 k 2
8 1 1 3 = 1 k 4
D e t e c l 0 0 0 0 6 4
c
A d j u s l r n e n t R a n g e 1
o l A D C ( a d j . n o . 5 )
C h e c k F l 1 0 . R 1 1 2
R 1 1 0 = 1 k 0 5
R 1 1 2 = A d j u s t r n g
9 k 5 3 . . . 1 2 k 4
F 1 1 0 i R 1 r 2 - 1 k A )
R e i e r t o D
D
C R
ange selecting input
l(Sin) 000064
l ( a 1 0 2 )
H i = 4 1 0 2 / 2 3
|
L o g c 0 ( - 8 . 5 v )
R e i e r t o G
C h e c k O 0 0 0 5 9
r a n g r n q c o u n r e r
E
A d j u s l m e n l R a n g e 2
O l A D C ( a d i . n o . 4 )
C h e c k R 1 1 1 , B l l 4 8 1 1 1 : 1 0 k 5
R 1 1 4 = a d j u s t i n g
9 5 k . . 1 2 4 k
R 1 1 1 / / F 1 1 4
= = 1 0 k